Answer to Question #111322 in General Chemistry for Carson Phillips

Question #111322

How much volume of strong base @ 0.15 M concentration would be needed to neutralize 360 mls of 0.5 M
strong acid?

Expert's answer

C(base)V(base)=C(acid)V(acid)

0.15*V(base)=0.5*0.36

V(base)=1.2 L

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