82 mg of solute is mixed into a 0.35 L solution. At a temperature of 37°C and an osmotic pressure of 3.2 x 10-3 atm, calculate the molar mass of the solute.
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Expert's answer
2020-04-24T13:35:11-0400
82 x 0.082 x 310/1000 x 3.2 x 10-3 x 0.35 = 1,861.10714
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