Answer to Question #111019 in General Chemistry for Juan

Question

How many grams of H 2 O could be produced from the reaction of 70.8 grams of Mg(OH) 2 ? Given the equation , Mg(OH) 2 (aq)+2 HCl(aq) MgCl 2 (aq)+2 H 2 O(l)

Answer 1

mole ratio=Mg(OH)₂: H₂O= 1:2

$moles= mass/RMM$

If 70.8g of Mg(OH)₂ react then 70.8/58.3=1.214 moles reacted

therefore 2.428 moles of water was produced.

mass of water=2.428*18=43.7g