Question

Calculate the molarity of 32.25 grams of NaCl in 2.0 Liters of solution.

Answer 1

$\frac{m}{M}=\frac{32.25}{58.443}=0.55 mole$

$molarity=\frac{n}{V}=\frac{0.55}{2.0}=0.275mole/L$