Question #110845
Calculate the molarity of 0.060 moles of NaHCO3 in 1500. mL of solution.
1
Expert's answer
2020-04-20T15:08:21-0400

molarity=nV=0.0601.5=0.04mole/Lmolarity=\frac{n}{V}=\frac{0.060}{1.5}=0.04 mole/L


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