Half-reactions:
cathode: Cu2+ + 2 e- = Cu
anode: Na - e- = Na+
Overall:
Cu2+ + 2 Na = Cu + 2 Na+ (ionic form)
CuCl2 + 2 Na = Cu + 2 NaCl (example of complete form)
Cell standard potential:
E0 = E0(Cu2+/Cu) - E0(Na+/Na) = 0.337 + 2.710 = 3.047 V
Reaction is spontaneous in the forward direction (because E0 > 0).
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