We will use Law of dilution for finding the volume here
M1V1=M2V2M_1V_1=M_2V_2M1V1=M2V2
10×6=x×0.210\times6=x\times0.210×6=x×0.2
x=300 mL will be total volume of solution
So, volume of water added= 300 -10 = 290 mL
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