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Answer to Question #110347 in General Chemistry for Thomas Velez
Question #110347
What mass of C6H12O6 (glucose) is needed to prepare 450. mL of a 0.650 M solution of glucose in water
Expert's answer
m(C6H12O6)=Mr(C6H12O6)*C(C6H12O6)*V(C6H12O6)=180*0.65*0.45=52.65 g
Answer: 52.65 g of C6H12O6 (glucose) is needed to prepare 450. mL of a 0.650 M solution of glucose in water
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