molar mass of NaCl= 23+35.5= 58.5 g/mole
and molar mass of H2O= 18 g/mole
so, here given mass of NaCl= 58.5 and mass H2O = 180 g
Now,
Mole of NaCl="n_1=\\frac{mass}{molar mass}=\\frac{58.5}{58.5}=1"
mole of H2O="n_2=\\frac{mass}{molar mass}=\\frac{180}{18}=10"
mole fraction of NaCl="x_1= \\frac{n_1}{n_1+n_2}= \\frac{1}{1+10}=0.091"
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