HClO4(aq) +H2O(l)→ H3O+(aq) ClO4−(aq)HClO_4 (aq) \space + H_2O (l) \to \space H_3O^+ (aq) \space ClO_4^- (aq)HClO4(aq) +H2O(l)→ H3O+(aq) ClO4−(aq)
pH=−log[H+]pH = -log[H^+]pH=−log[H+]
[H3O+]=[H+]=[ClO4−]=0.18mol/L[H_3O^+] = [H^+] = [ClO_4^-] = 0.18 mol/L[H3O+]=[H+]=[ClO4−]=0.18mol/L
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments