Solution.
I) Using the Ideal Gas Equation
V = 18 L;
n = 4.5 mol;
T = 298 K;
PV = nRT;
R = 0.0821 L atm K-1 mol-1.
P = nRT/V = (4.5 x 0.0821 x 298)/18= 6.12 atm;
II)Using Van der Waals equation
a =4.453 L2 atm mol-2;
b = 0.05220 L mol-1;
(P + an2/V2)(V - nb) = nRT;
(P + 4.453x(4.5)2/182)(18-4.5 x0.05220)=4.5x 0.0821 x 298;
(P + 0.28)x17.77=110.1;
P + 0.28=6.20;
P=6.20-0.28=5.92 atm.
Answer: I) P=6.12 atm;
II) P=5.92 atm.
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