Answer on Question #109610, Chemistry, General Chemistry
9.50*10^22 formula units of lead (II) nitrate is how many moles?
Solution:
Number of moles of lead (II) nitrate can be determine as:
n (Pb(NO3)2) = N/Na, where N = 9.50*1022; Na is Avogadro's number which equals 6.022*1023 mol-1.
Thus:
n (Pb(NO3)2) = 9.50*1022/6.022*1023 = 0.158 (moles)
Answer: n (Pb(NO3)2) = 0.158 moles.
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