Solution.
1.
This figure shows graphs of concentration-time dependencies for 0, 1, 2, and 3 reaction orders. As we can see, a linear dependence of order 1 is observed for these values.
2.
"k = \\frac{1}{t} \\times ln(\\frac{C0}{C})"
k = 0.0025
3.
"C0 = e^{kt} \\times C"
"C0 = e^{0.0025 \\times 21} \\times 1.26 = 1.33 \\ M"
4.
"t(1\/2) = \\frac{ln(2)}{k}"
t(1/2) = 277.26 min
Answer:
1.
1 order
2.
k = 0.0025
3.
1.33 M
4.
t(1/2) = 277.26 min
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