Here, the reaction is as follows
H2+O2⟶2H2O
Here given that mass of H2=8.0 g and mass of H2O= 9.0 g
moles of H2=molarmassgivenmass=28=4 mole and
moles of O2=molarmasSgivenmass=329 =0.2812
so here O2 is limiting reagent and
massof H2O=18×.2812=5.06g
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