Let "x" litres of a 12% sulphuric acid solution should be mixed with 5L of a 2% sulphuric acid solution to obtain a 8% solution of sulphuric acid.
Concentration of mixture "=8=(12*x+2*5)\/(x+5)"
"\\implies 8x+40=12x+10 \\implies 3x=30 \\implies x=10L"
Thus, 10 litres of a 12% sulphuric acid solution should be mixed with 5L of a 2% sulphuric acid solution to obtain a 8% solution of sulphuric acid.
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