Answer to Question #109371 in General Chemistry for mya 15

Question

Given that Kw for water is 2.4×10−14 at 37C, calculate the pH of a neutral aqueous solution at 37C, which is the normal human body temperature

Answer 1

K_w=[H⁺]*[OH^-];

If the aqueous solution is neutral, [H⁺]=[OH^-], then

[H+]=[OH-]=√K_w=√2.4*10^-14 = 1.55×10^-7

pH=-lg[H+]=6.8