Solution.
C= 0.385 J/g · K;
m=204 g;
Tfinal=28.5 °C=301.5 K;
Tinitial= –17.7 °C=255.3 K;
"\\Delta"T=Tfinal - Tinitial; ΔT=301.5 K - 255.3 K =46.2 K;
q=C · m ·ΔT;
q=0.385 J/(g · K) · 204 g ·46.2 K=3628.5 J.
Answer: q=3628.5 J.
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