Question

A sample that contains 2.54 mol of a gas at 298 K has a pressure of 2.16 atm. What is its volume?

Answer 1

According to the equation of Mendeleev-Clapeyron for gases ($p•V = \nu•R•T$ ), we can determine the volume using this formula (considering that 2.16 atm = 202650 Pa, Pa = N/m², J = N•m):

$V = (\nu•R•T) / p$ = (2.54(mol)•8.31((N•m)/(mol•K))•298(K)) / 202650(N/m²) = 0.03 m³ = 30 ml

Answer: V=30 ml