Answer to Question #109061 in General Chemistry for Jamie Strong

Question

If 7.0 moles of nh3 reacts with 14 moles of o2, how many moles of no2 will be produced?

Calculate how many moles of excess reactant will remain

Answer 1

4NH3 + 7O2 = 4NO2 + 6H2O

According to the equation NH3 reacts completely, O2 is in the excess.

7 mol of NO2 will be produced.

According to the equation 7mol*7/4 = 12. 25 mol of O2 reacts.

14 - 12.25 = 1.75 mol of O2 will remain.