The equation for the reaction of the formation of water from oxygen and hydrogen:
2H2 + O2 "\\to" 2H2O
"\\nu"(H2O) = "m\/M" = 100(g) / 18(g/mol) = 5.56 mol = "\\nu"(H2)
"\\nu" (O2) = "\\nu" (H2O) "\u2022 1\/2" = 5.56(mol) • 1/2 = 2.78(mol)
m(O2) = "\\nu \u2022 M" = 2.78(mol) • 32(g/mol) = 88.96 g
m(H2) = "\\nu\u2022M =" 5.56(mol) • 2(g/mol) = 11.12 g
Answer: m(O2)=88.96 g; m(H2) = 11.12 g
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