Answer to Question #108877 in General Chemistry for Marry

Question

determine the Celsius temperature of 2.49 mol of gas contained in a 1.00-L vessel at a pressure of 143 kPa

Answer 1

According to the equation of Mendeleev-Clapeyron for gases ($p•V = \nu•R•T$), we can determine the temperature using this formula (considering that Pa = N/m² , L = m³ and J = N•m):

$T = (p•V) / (\nu•R)$ = (143(N/m²) • 10³ • 1(m³)) / (2.49(mol) • 8.31((N•m)/(mol•K))) = (143•10³(N•m))/20.69((N•m)/K) = 6910 K = 6637^oC

Answer: T=6637^oC