Question

Determine whether each of the following ionic substances is highly or slightly soluble in
water. For those that are highly soluble write their dissociation equations and calculate the
concentration of the ions assuming all solutions are 0.75mol/L
a) CaCO 3 b) AgBr
c) NaNO 3 d) CuCl
e) NaCH 3 COO f) AlPO 4
g) CuS h) Pb(SO 4 )

Answer 1

Solution.

NaNO3→ Na⁺+NO₃^-;

CuCl₂→ Cu²⁺+2Cl^-;

NaCH₃COO→ Na⁺+CH₃COO^-;

Since these salts are strong electrolytes, the equilibrium ion concentration is equal to the salt concentration:

[NO3^-] = C_NaNO3=0.75mol/L;

[Cl^-] = C_CuCl2=0.75mol/L;

[CH₃COO^-]= C_NaCH3COO=0.75mol/L;

Answer:

NaNO₃→ Na⁺+NO₃^-;

CuCl₂→ Cu²⁺+2Cl^-;

NaCH₃COO→ Na⁺+CH₃COO^-;

[NO₃^-] = 0.75mol/L;

[Cl^-] = 0.75mol/L;

[CH₃COO^-]=0.75mol/L;