Question

The elementary reaction


2

H

2

O

(

g

)

−

⇀

↽

−

2

H

2

(

g

)

+

O

2

(

g

)

2

H

2

O

(

g

)

↽

−

−

⇀

2

H

2

(

g

)

+

O

2

(

g

)


proceeds at a certain temperature until the partial pressures of

H

2

O

H

2

O

,

H

2

H

2

, and

O

2

O

2

reach

0.063

bar

0.063

bar

,

0.0024

bar

0.0024

bar

, and

0.0017

bar

0.0017

bar

, respectively, at equilibrium. What is the value of the equilibrium constant at this temperature

Answer 1

$K_p=\frac{p_{H_2}^2\times p_{O_2}}{p_{H_2O}^2}=\frac{0.0024^2\times0.0017}{0.063^2}=0.2467\times10^{-5}bar$