According to the ideal gas law:
"\\frac{P_{1}V_{1}}{T_{1}}=\\frac{P_{2}V_{2}}{T_{2}},"
or
"P_{2}=\\frac{P_{1}V_{1}T_{2}}{T_{1}V_{2}}=\\frac{101.3kPa*32L*248.5K}{45L*273K}=65.6kPa(0.65atm)."
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