Solution:
P1V1T1=P2V2T2\frac {P_1 V_1} {T_1} = \frac {P_2 V_2} {T_2}T1P1V1=T2P2V2
V2=P1V1T2P2T1V_2=\frac {P_1 V_1 T_2} {P_2 T_1}V2=P2T1P1V1T2
V2=785(mmHg)×3.84(mL)×273(K)760(mmHg)×298(K)V_2=\frac {785 (mmHg) \times 3.84 (mL) \times 273 (K)} {760 (mmHg) \times 298 (K)}V2=760(mmHg)×298(K)785(mmHg)×3.84(mL)×273(K)
V2=3.63(mL)V_2= 3.63 (mL)V2=3.63(mL)
Answer:3.63 mL
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