Question

Helium boils at –178 o C and a

pressure of 1900 mmHg. What will the

pressure be if the temperature is raised

to 0 o C and the volume is kept constant?

Answer 1

$$\frac{P_1}{T_1}=\frac{P_2}{T_2}\\now, P_1= 1900\ mm Hg\\T_1=273-178\ K=95\ K\\$$

$$T_2= 273\ K\\$$

Putting all values,

We get ,

$$\frac{1900}{95}=\frac{P_2}{273}\\or\\P_2=5460mm\ of Hg$$