Answer to Question #107763 in General Chemistry for Ashton Ball

Question

A glucose solution in water is labelled as 20%. The density of the solution is 1.20g/mL. What is the molarity if the solution?

Answer 1

M_{раствора}=n(C₆H₁₂O₆)/V_{раствора}

If the mass of the solution = 100g, then m(C₆H₁₂O₆)=100*0.2=20g

n(C6H12O6)= m(C₆H₁₂O₆)/M(C₆H₁₂O₆)=20/180=0.11mol

m=ρ*V

V=m/ρ=100/1.2=83.3ml=0.083l

Mраствора=n(C₆H₁₂O₆)/V_{раствора}=0.11/0.083=1.33mol/l