a) pV=nRT n= pV/RT = 1.02 x 0.296 / 0.082 x 299.4 = 0.0123 mol and 0.0123/1.5 =0.00819851087 M.
pH= 2.086.
b) antilog(-1.6)= 0.0251 M.
5.3 x 0.0251=0.13303moles.
0.13303 x 36.5 =4.855595 g
4.855595x100/ 36.0 = 13.4877639 g.
13.4877639/1.179 = 11.4400033 ml.
1) 0.522878745
2) 1.3
3) 1.6
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