Answer to Question #107260 in General Chemistry for Iana

Question

The reaction of 6.70 g of carbon with excess O2 yields 10.3 g of CO2. What is the percent yield of this reaction?

Answer 1

C+O₂=CO₂

Ƞ=m/m_t

m(CO₂)=10.3g

n(C)=m(C)/M(C)=6.70/12=0.558mol

According to the equation of a chemical reaction n(CO₂)=n(C)=0.558mol

m_t(CO₂)=n(CO₂)*M(CO₂)=0.558*(12+16*2)=0.558*44=24.57g

 

Ƞ=(m/m_t)*100%=(10.3/24.57)*100%=41,9%

 

Answer: 41,9%