Question

A balloon is filled with 20 L of air at a pressure of 2 atm. What is the volume of the balloon if the pressure is
changed to 5 atm?

Answer 1

When the process is slow enough, the temperature should be constant. Thus, we can use the following expression:

$P_{1}V_{1}=P_{2}V_{2};$

$V_{2}=\frac{P_{1}V_{1}}{P_{2}};$

$V_{2}=\frac{2atm*20L}{5atm}=8L.$

The balloon will be squeezed to some 8 L of volume.