When the process is slow enough, the temperature should be constant. Thus, we can use the following expression:
"P_{1}V_{1}=P_{2}V_{2};"
"V_{2}=\\frac{P_{1}V_{1}}{P_{2}};"
"V_{2}=\\frac{2atm*20L}{5atm}=8L."
The balloon will be squeezed to some 8 L of volume.
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