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Answer to Question #107083 in General Chemistry for Dana C Bushman
Question #107083
How many grams of lithium hydride are necessary to completely react with 10.3 grams of titanium(IV) chloride in the reaction below?
TiCl4(l) + 4LiH(s) Ti(s) + 4LiCl(s) + 2H2(g)
TiCl4(l) + 4LiH(s) Ti(s) + 4LiCl(s) + 2H2(g)
Expert's answer
m(LiH)=m(TiCl4)*M(LiH)*4/M(TiCl4)=10.3(g)*7.95(g/mol)*4/189.68(g/mol)=1.73g
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