Question

a solution is prepared by dissolving 2.50 g of sodium chromate, Na2CrO4, in 50.0 g of water. calculate the percent of the solute in this solution

Answer 1

$$w(Na_2CrO_4) = m(Na_2CrO_4)/m(solution)$$

$$w(Na_2CrO_4) = 2.50/(2.50+50.0) = 0.048 = 4.8 \%$$