Answer to Question #106984 in General Chemistry for Taylor

Question

If 9.0 of oxygen gas are consumed with excess propane in the following reaction, how many miles of carbon dioxide will be produced?

C3H8(g)+5O2(g)= 3CO2(g)+4H2O(g)

Answer 1

m (O2) = 9.0 g

M = 32.0 g/mol

n = 9.0 / 32.0 = 0.28125 mol

n (CO2) = 3/5 * 0.28125 = 0.16875 mol

V = 0.16875 * 22.4 L/mol = 3.78 L = 3,780 mL

if 9.0 is volume, for example 9.0 mL, then 9.0 * 3/5 = 5.4 mL CO2 is produced.