Answer to Question #106638 in General Chemistry for Sebastian Adame

Question

What volume (in mL) of concentrated nitric acid (HNO3, 15.8 M) would be needed to make 100.0 mL of a3.00 M solution?
Your answer

Answer 1

$$n = cV$$

$$n(HNO_3) = 3.00M*0.100L = 0.3mol$$

$$V(HNO_3)_{initial} = n/c = 0.3mol/15.8M = 0.0189L = 18.9 mL$$

Answer: 18.9 mL