We are not provided with the molar mass of the fish molecules so lets assume it as x
moles of fish molecules in 12.5 kg of fish meat = "12.5\\times10^3\/x"
molecules contained in the 12.5 kg of meat = "\\frac{12.5\\times10^3}{x}\\N_A"
It is said in the question that 1.76 parts per million is mercury
So mercury molecules present ="\\frac{12.5\\times10^3}{x}\\N_A\\times10^{-7}\\times1.76"
If we divide it by NA we will get number of moles of mercury and if we will further multiply it by the molar mass of the mercury we will get the mass of mercury present
Since you have not provided the all data we are unable to tell you the answer
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