Answer to Question #106104 in General Chemistry for hadeel

Question

According to the following reaction, how many grams of aluminum sulfate will be formed upon the complete reaction of 22.5 grams of sulfuric acid with excess aluminum oxide?

aluminum oxide (s) + sulfuric acid (aq) aluminum sulfate (aq) + water (l)

Answer 1

Al₂O₃ + 3H₂SO₄ = Al₂(SO₄)₂ + 3H₂O

n(H2SO4) = m/M = 22.5g/98g/mol = 0.23 mol

According to the equation:

n(Al2(SO4)2) = 0.23/3 = 0.0767 mol

m(Al2(SO4)2) = n*M = 0.0767mol*342g/mol = 26.23 g