Question

Lead iodide and lead carbonate are insoluble. Which 2 soluble salts could you use in the preparation of each substance? Write
a.) a word equation
b.) a symbol equation
c.) an ionic equation
to represent the reaction taking place.

Answer 1

Two soluble metal salts react with each other to form one soluble salt and one insoluble salt. Lead nitrate solution and potassium iodide solution react to produce solid lead iodide, leaving soluble potassium nitrate in solution

$Pb(NO_3)_2+KI\to PbI_2+KNO_3\\Pb^{2+}(aq)+I^-(aq)\to PbI_2(s)$

Lead carbonate can be prepared by reacting Lead nitrate and sodium carbonate and Lead carbonate is precipitated along with sodium nitrate

$Pb(NO_3)_2 + Na_2CO_3 → PbCO_3 + 2NaNO_3\\ Pb^{2+}(aq) + CO3^{2-} (aq) → PbCO_3(s)$