Question

Which of the above equilibria is forced to shift furthest to the left? Explain.


- Lead nitrate and Sodium chloride

- Lead chloride and Sodium chromate

-Lead chromate and Sodium sulphide

Answer 1

The equilibrium is forced to shift in furthest to the left when the product formed is not favourable i.e. when the the $\Delta$G of the reaction is positive

- Lead nitrate and Sodium chloride

When sodium chloride solution is added to lead nitrate solution then it results in the formation of a precipitate of lead chloride and sodium nitrate. The reaction equation for this chemical reaction is as follows. $NaCl(aq)+Pb(NO_3)_2(aq)\to PbCl_2(ppt)+NaNO_3(aq)$

- Lead chloride and Sodium chromate

in this sodium chromate being a yellow solid and the other being lead chloride is which is itself a precipitate and becomes a little soluble in hot water so there will be hardly any reaction and that too will happen at very high temperature Hence this will shift furthest to the left