a.From this reaction: 2NaN3 --> 2Na + 3N2 ,
a proportion can be made:
80/(2*65)=x/(2*23) ;
Where x - mass of Na produced;
23 - molar mass of Na;
80 - mass of NaN3;
65 - molar mass of NaN3;
2 - stoichiometric values of NaN3 and Na in this reaction;
Answer: m(Na)=28.3g;
b. 80/(2*65)=y/22.4*3;
y - volume of N2 in the first reaction;
y=41.35
Answer: V1(N2)=41.35 liters;
c. 28.3/(23*10)=z/22.4 ;
z - volume of N2 in the second reaction;
z= 2.76;
Answer: V2(N2)= 2.76 liters;
d. Vtotal(N2)= V1(N2) + V2(N2) = 2.76 + 41.35 = 44.11 liters;
e. φ=54.5/44.11=1.235= 123.5%. In real world condition the temperature and pressure can be different than stp (273 K; 1 atm). This is the main reason of the differense, because when temperature is higher (293-298 K) and pressure is lower, the volume of prodused gas will be higher.
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