Answer to Question #103661 in General Chemistry for adam

Question #103661

fe302+4h2=3fe+4h2o when 16.0g of fe3o2 react with excess hydrogen 5.9g fe prduced what is the yeild

Expert's answer

Fe₃O₂ + 4H₂ = 3Fe + 4H₂O

16 g x g

(56*3+16*2)g 3*56 g

x = 13.44 g

yeild = 5.9 / 13.44 * 100% = 43.9%

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