Answer to Question #103588 in General Chemistry for Afolabi Soyemi

Question

What volume of hydrogen at s.t.p will be produced when 48g of magnesium reacts completely with dilute hydroxhloric according to the following equation Mg+2HCL=MgCl+H

Answer 1

According to the following equation Mg+2HCL=MgCl₂+H₂ 1 mole of magnesium produces 1 mole of hidrogen. From an equation n=m/Mr we can find the quantity of Mg. n(Mg)= 48/24=2 mole. So 2 mole of Mg produces 2 mole of H₂. 1 mole of gas at s.t.p has a volume of 22.4 liters, so volume of 2 mole H₂ is 2*22.4=44.8 liters.

n=m/Mr;

n=V/V_m; V_m=22.4 liters

V/V_m = m/Mr;

V=m*V_m/Mr;

V=48*22.4/24 = 44.8 l