Answer to Question #103497 in General Chemistry for Emily Fitzsimmons

Question

Light with a frequency of 6.85 × 1014 Hz lies in the violet region of the visible spectrum. What is the wavelength of this frequency of light?

Answer 1

$\nu = 6.85 × 10^{14} Hz$

$\lambda =c/ \nu$ , where

$c=3*10^8m/s$ --- speed of light

$\implies \lambda = (3*10^8)/(6.85*10^{15})$

$\implies \lambda = 4.38*10^{-8}=43.8nm$