It is given that number of moles of gas =0.5 mole
Temperature of gas =140 K
Pressure = 1.2 atm
we know that , using ideal gas equation
pV= nRT
here, R= gas constant whose value is .082 L atm mol -1K -1
1.2×V=0.5×0.082×1401.2 \times V = 0.5 \times 0.082\times 1401.2×V=0.5×0.082×140
V=0.5×0.082×1401.2V= \frac{0.5\times0.082\times 140}{1.2}V=1.20.5×0.082×140
V=4.783 L
So, volume of gas will be V= 4.783 L
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