Answer to Question #102798 in General Chemistry for ruba

Question #102798

lead (II) sulfide has a composition of 86.6% lead and 13.4% sulfur . if 10.5 g of lead reacts to form lead (II) sulfide . What mass of sulfur reacts?

Expert's answer

86.6/201:13.4/32=1:1.

PbS.

Pb+S=PbS.

(10.5/201) x 32= 1.67164179 g of S

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