C2H5OH + 3O2"\\to" 2CO2 + 3H2O
a) What mass of oxygen is required to react with 1200 g of ethanol
n(C2H5OH) =1200(g)/46(g/mol)=26.09 mol
n(O2)=26.09/1=X/3 n of O2=78.3 mol O2
m(O2)= n*M =78.3*32=2504 g
b) If 655 g of water is produced, what mass of ethanol is burned?
n(H2O) =655g/18(g/mol)=36.39 mol
n of H2O/n of H2O = n of C2H5OH/n of C2H5OH 36.39/3=X/1 n of C2H5OH=12.13 mol m(C2H5OH)=12.13 X (2(12)+6(1)+16) =558 g
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