Answer to Question #101531 in General Chemistry for Bajsb

Question

How many moles of Chlorine gas at 120 degrees C and 33.3 atm would occupy 12L?

Answer 1

$T=393K;P=33.3atm;V=12L;n=?$

Using $PV=nRT$ ; we get;

$n=33.3*12/(0.0821*393)$

$=12.385mol$