First, we calculate the molar mass of oxygen in this compound.
M (O) = 16 * 3 = 48 g/mol.
Next, we calculate the molar mass of the entire compound. Write down the solution.
M (KClO3) = 39 + 35,5 + 16 * 3 = 122,5 g / mol.
Next, we find the mass fraction of oxygen in this compound.
W = 48/122,5 * 100 % = 39,1 %.
This means that the mass fraction of oxygen is 39.1 %
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