Question

Suppose that 4 mol of gas is measured at 4 atm pressure to have a volume of 3 L, a temperature of 270 K. If the conditions change such that there are 3 mol at 2 atm and at 300 K, what is the new volume?

Answer 1

PV=nRT

V=nRT/p

V= 3 [mol] • 8,314 [Pa•m³/(mol•K)] • 300 [K]/202650 [Pa] = 0,0369 m³ or 36,92 l