Suppose that 4 mol of gas is measured at 4 atm pressure to have a volume of 3 L, a temperature of 270 K. If the conditions change such that there are 3 mol at 2 atm and at 300 K, what is the new volume?
1
Expert's answer
2019-12-18T06:12:58-0500
PV=nRT
V=nRT/p
V= 3 [mol] • 8,314 [Pa•m3/(mol•K)] • 300 [K]/202650 [Pa] = 0,0369 m3 or 36,92 l
Comments
Leave a comment