Answer to Question #100053 in General Chemistry for Malathy

Question

When copper(I) sulfide is partially roasted in air (reaction with O2), copper(I) sulfite is formed first. Subsequently, upon heating, the copper sulfite thermally decomposes to copper(I) oxide and sulfur dioxide. Write balanced chemical equations for these two reactions.

Answer 1

Solution.

1.

$2Cu2S + 3O2 = 2Cu2SO3$

2.

$Cu2SO3 = Cu2O + SO2$

Answer:

1.

$2Cu2S + 3O2 = 2Cu2SO3$

2.

$Cu2SO3 = Cu2O + SO2$