In 111 mole of CCl4CCl_4CCl4 number of ClClCl atoms present are 4×Na4\times Na4×Na
Hence in 222 moles of CCl4CCl_4CCl4 number of atoms of ClClCl are 8×Na=4.8184×1024atoms8\times Na=4.8184\times10^{24}atoms8×Na=4.8184×1024atoms
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